5j^2-26j+5=0

Solution for 5j^2-26j+5=0 equation:

Simplifying
5j2 + -26j + 5 = 0

Reorder the terms:
5 + -26j + 5j2 = 0

Solving
5 + -26j + 5j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(1 + -5j)(5 + -1j) = 0

Subproblem 1
Set the factor '(1 + -5j)' equal to zero and attempt to solve:

Simplifying
1 + -5j = 0

Solving
1 + -5j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5j = 0 + -1
-5j = 0 + -1

Combine like terms: 0 + -1 = -1
-5j = -1

Divide each side by '-5'.
j = 0.2

Simplifying
j = 0.2
Subproblem 2
Set the factor '(5 + -1j)' equal to zero and attempt to solve:

Simplifying
5 + -1j = 0

Solving
5 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1j = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1j = 0 + -5
-1j = 0 + -5

Combine like terms: 0 + -5 = -5
-1j = -5

Divide each side by '-1'.
j = 5

Simplifying
j = 5
Solution
j = {0.2, 5}